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Re: U2-darn few bugs...
- Subject: Re: U2-darn few bugs...
- From: cld@xxxxxxxx
- Date: Fri, 24 Feb 2006 17:32:17 +0000
It's a matter of definition, I think. The negative exponent is defined to be the reciprocal of the positive exponent. That is, x^(-n) = 1/(x^n). As to why this definition makes sense, here is one explanation:
http://faculty.ed.umuc.edu/~swalsh/Math%20Articles/Exponents.html
Another reason is that for n>0 and x>0, the function (or set of functions) y=n^x is continuous (if you graph it for any n, you get an unbroken line, with the y-axis as an asymptote), which is nice since y=x is also continuous (an unbroken straight line).
So you see, it's a cinch to translate negative integer exponents into code.
--
Carl Distefano
cld@xxxxxxxx